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(A) The starting material is $4$-chlorotoluene. The final product is $4$-chloro-$2$-bromo-$5$-nitrobenzoic acid.Step $1$: Electrophilic aromatic subst

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$(i) \ Br_2 + FeBr_3$$(ii) \ KMnO_4$ and heat$(iii) \ HNO_3$ and $H_2SO_4$

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(A) The starting material is $4$-chlorotoluene. The final product is $4$-chloro-$2$-bromo-$5$-nitrobenzoic acid.Step $1$: Electrophilic aromatic substitution with $Br_2$ and $FeBr_3$ introduces a bromine atom at the ortho position relative to the methyl group (due to the activating nature of the $-CH_3$ group).Step $2$: Oxidation of the methyl group using $KMnO_4$ and heat converts the $-CH_3$ group into a carboxylic acid group $(-COOH)$.Step $3$: Nitration using $HNO_3$ and $H_2SO_4$ introduces a nitro group $(-NO_2)$ at the position ortho to the $-COOH$ group,which is the meta position relative to the $-Cl$ and $-Br$ substituents,following the directing effects of the existing groups.

Which of the following procedures would be best for achieving the following reaction?

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$Ethyl$ benzene cannot be prepared by:

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